(Deatsville, AL, USA). The Sock Drawer: Probability and Statistics Problem A drawer contains red socks and black socks. Two drawn at random. The students get confused. When two socks are drawn at random, the probability that both are red is 1/2. Case 2 : 2 pair of socks are present in the drawer. In a drawer $r$ red, $b$ blue, and $g$ green socks. Solution 1 To start with, instead of looking for a matching pair, let's find the probability that both socks are red. We care about your data privacy. Hence, 3. |Algebra| The following solution uses the Principle of Inclusion / Exclusion, abbreviated PIE. The probability of getting one sock red is $\displaystyle\frac{r}{r+b+g}.$ Assuming that the first sock is red, the probability of getting the second red sock is $\displaystyle\frac{r-1}{r+b+g-1}.$, When it comes to calculating probabilities, colors do not make much difference: analogous argument applies to blue and green socks, implying that the probability of getting two blue socks is $\displaystyle\frac{b(b-1)}{(r+b+g)(r+b+g-1)}$ and that of getting green socks is $\displaystyle\frac{g(g-1)}{(r+b+g)(r+b+g-1)}.$ The answer to the question is then, $\displaystyle\frac{r(r-1)+b(b-1)+g(g-1)}{(r+b+g)(r+b+g-1)}.$.
That should be what you do first with an easy assignment as this. &=\frac{r(r-1)}{(r+b+g)(r+b+g-1)}. The first and the second draw might result in 2 socks of different color. This question was asked in Aamaon. So, the task is to find the minimum number of socks to be drawn at random to be sure that he/she gets the pair of socks of the same color? Case 1 : A pair of socks are present, hence exactly 2 draws for the socks to match. Start Now. The answer to this is, $\displaystyle\frac{4\cdot 3+5\cdot 4+2\cdot 1}{11\cdot 10} = \frac{17}{55}.$, |Contact| Note: If a +1 button is dark blue, you have already +1'd it. It would seem you can either make a pair or have a mismatched pair, and that both of those events would have equal chances, making for a 50 percent probability. |Front page| The question was posted at the Probability problems page, with 4 red, 5 blue, 2 green socks. My interpretation of the problem statement is that we are asked to find the probability that at least one of the three pairs of socks drawn is a match.
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(Deatsville, AL, USA). The Sock Drawer: Probability and Statistics Problem A drawer contains red socks and black socks. Two drawn at random. The students get confused. When two socks are drawn at random, the probability that both are red is 1/2. Case 2 : 2 pair of socks are present in the drawer. In a drawer $r$ red, $b$ blue, and $g$ green socks. Solution 1 To start with, instead of looking for a matching pair, let's find the probability that both socks are red. We care about your data privacy. Hence, 3. |Algebra| The following solution uses the Principle of Inclusion / Exclusion, abbreviated PIE. The probability of getting one sock red is $\displaystyle\frac{r}{r+b+g}.$ Assuming that the first sock is red, the probability of getting the second red sock is $\displaystyle\frac{r-1}{r+b+g-1}.$, When it comes to calculating probabilities, colors do not make much difference: analogous argument applies to blue and green socks, implying that the probability of getting two blue socks is $\displaystyle\frac{b(b-1)}{(r+b+g)(r+b+g-1)}$ and that of getting green socks is $\displaystyle\frac{g(g-1)}{(r+b+g)(r+b+g-1)}.$ The answer to the question is then, $\displaystyle\frac{r(r-1)+b(b-1)+g(g-1)}{(r+b+g)(r+b+g-1)}.$.
That should be what you do first with an easy assignment as this. &=\frac{r(r-1)}{(r+b+g)(r+b+g-1)}. The first and the second draw might result in 2 socks of different color. This question was asked in Aamaon. So, the task is to find the minimum number of socks to be drawn at random to be sure that he/she gets the pair of socks of the same color? Case 1 : A pair of socks are present, hence exactly 2 draws for the socks to match. Start Now. The answer to this is, $\displaystyle\frac{4\cdot 3+5\cdot 4+2\cdot 1}{11\cdot 10} = \frac{17}{55}.$, |Contact| Note: If a +1 button is dark blue, you have already +1'd it. It would seem you can either make a pair or have a mismatched pair, and that both of those events would have equal chances, making for a 50 percent probability. |Front page| The question was posted at the Probability problems page, with 4 red, 5 blue, 2 green socks. My interpretation of the problem statement is that we are asked to find the probability that at least one of the three pairs of socks drawn is a match.
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20 Oct

matching pair of socks problem

Posted in Uncategorized by on October 20, 2020 @ 11:53 am

It's easy to do. How? Note: Not all browsers show the +1 button. He wants to sell as many socks as possible, but his customers will only buy them in matching pairs. Answer To Amazon’s Pair Of Socks Puzzle The tempting answer is 50 percent. Next T lines contains an integer N which indicates the total pairs of socks present in the drawer. If you like this Site about Solving Math Problems, please let Google know by clicking the +1 button. In its worst case scenario, how many socks (x) should Tom remove from his drawer until he finds a matching pair? Logging in registers your "vote" with Google. P(2\mbox{ red socks})&=C^{r}_{2}/C^{r+b+g}_{2}\\

(Deatsville, AL, USA). The Sock Drawer: Probability and Statistics Problem A drawer contains red socks and black socks. Two drawn at random. The students get confused. When two socks are drawn at random, the probability that both are red is 1/2. Case 2 : 2 pair of socks are present in the drawer. In a drawer $r$ red, $b$ blue, and $g$ green socks. Solution 1 To start with, instead of looking for a matching pair, let's find the probability that both socks are red. We care about your data privacy. Hence, 3. |Algebra| The following solution uses the Principle of Inclusion / Exclusion, abbreviated PIE. The probability of getting one sock red is $\displaystyle\frac{r}{r+b+g}.$ Assuming that the first sock is red, the probability of getting the second red sock is $\displaystyle\frac{r-1}{r+b+g-1}.$, When it comes to calculating probabilities, colors do not make much difference: analogous argument applies to blue and green socks, implying that the probability of getting two blue socks is $\displaystyle\frac{b(b-1)}{(r+b+g)(r+b+g-1)}$ and that of getting green socks is $\displaystyle\frac{g(g-1)}{(r+b+g)(r+b+g-1)}.$ The answer to the question is then, $\displaystyle\frac{r(r-1)+b(b-1)+g(g-1)}{(r+b+g)(r+b+g-1)}.$.
That should be what you do first with an easy assignment as this. &=\frac{r(r-1)}{(r+b+g)(r+b+g-1)}. The first and the second draw might result in 2 socks of different color. This question was asked in Aamaon. So, the task is to find the minimum number of socks to be drawn at random to be sure that he/she gets the pair of socks of the same color? Case 1 : A pair of socks are present, hence exactly 2 draws for the socks to match. Start Now. The answer to this is, $\displaystyle\frac{4\cdot 3+5\cdot 4+2\cdot 1}{11\cdot 10} = \frac{17}{55}.$, |Contact| Note: If a +1 button is dark blue, you have already +1'd it. It would seem you can either make a pair or have a mismatched pair, and that both of those events would have equal chances, making for a 50 percent probability. |Front page| The question was posted at the Probability problems page, with 4 red, 5 blue, 2 green socks. My interpretation of the problem statement is that we are asked to find the probability that at least one of the three pairs of socks drawn is a match.

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